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From her eye, which stands 1,61 meters above the ground, Savannah measures the

angle of elevation to the top of a prominent skyscraper to be 24°. If she is standing at
a horizontal distance of 340 meters from the base of the skyscraper, what is the
height of the skyscraper? Round your answer to the nearest hundredth of a meter if
necessary

2 Answers

4 votes

Answer:

132.6 meters tall

Explanation:

it gave me the answer

User Mnaczenski
by
4.3k points
0 votes

Answer:

152.99 m

Explanation:

Using the solution diagram attached below :

We can obtain the height, h of skyscraper to the position of her eye level using trigonometry ;

Tan θ = opposite / Adjacent

Tan 24 = h / 340

h = tan 24 * 340

h = 151.37775

Hence, the height will be (h + distance from eyelevel to ground)

151.37775 + 1.61

= 152.98775

= 152.99 m

From her eye, which stands 1,61 meters above the ground, Savannah measures the angle-example-1
User Nick Toumpelis
by
4.5k points