Answer:
Explanation:
Given that:
at point (0, -2)

Taking the differential from the equation above with respect to x;

Collect like terms


Hence, the slope of the tangent line m can be said to be:

At point (0,-2)



m = 0
So, we now have the equation of the tangent line with slope m = 0 moving through the point (x, y) = (0, -2) to be:
(y - y₁ = m(x - x₁))
y + 2 = 0(x - 0)
y + 2 = 0
y = -2