Answer:
Explanation:
take angle A as reference angle
using cos rule
cos A = adjacent/hypotenuse
cos A =10/15
cos A =0.66
![A=cos^(-1) (0.6666)](https://img.qammunity.org/2022/formulas/mathematics/high-school/o9zynmflpzd950zdyqbzgouszvl2x33u84.png)
A=48.194
A=48.2
angle A + angle B + angle C =180 degree (being sum of interior angles of a triangle)
48.2 + angle B + 90 =180
138.2 + angle B =180
angle B =180-138.7
angle B =41.8
for BC
using pythagoras theorem
a^2 + b^2 = c^2
AC^2 + BC^2 = AB^2
10^2 + BC^2 = 15^2
100 + BC^2 = 225
BC^2 = 225-100
BC^2 = 125
![BC=√(125)](https://img.qammunity.org/2022/formulas/mathematics/high-school/1zm6d1iefgtvlynmlibbg4dov9llvhe5t2.png)
BC=5
![√(5)](https://img.qammunity.org/2022/formulas/mathematics/high-school/to902y7m239zcf8mzm9ryzwwpym8b0o9sf.png)
BC=11.2