Question

If the sum of three consecutive integers is 36 what is the smallest integer?

Answer 1

The smallest integer is 11.

Explanation:

Let the first integer be x.

Then the second will be (x + 1) and the third will be (x + 2).

The sum is 36. Hence:

`x+(x+1)+(x+2)=36`

Solve for x:

`3x+3=36`

So:

`3x=33`

Hence:

`x=11`

Our sequence is 11, 12, 13.

So, the smallest integer is 11.