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If the sum of three consecutive integers is 36 what is the smallest integer?

User Shaggydog
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1 Answer

4 votes

Answer:

The smallest integer is 11.

Explanation:

Let the first integer be x.

Then the second will be (x + 1) and the third will be (x + 2).

The sum is 36. Hence:


x+(x+1)+(x+2)=36

Solve for x:


3x+3=36

So:


3x=33

Hence:


x=11

Our sequence is 11, 12, 13.

So, the smallest integer is 11.

User Melony
by
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