Answer:
Part 1)
The height of the diving board is 19 feet.
Part 2)
Five seconds.
Part 3)
44 feet.
Explanation:
Joyce's dive is represented by the equation:
![h=-t^2+10t+19](https://img.qammunity.org/2022/formulas/mathematics/high-school/i1fzb3yl6xv81m1wkqvj336aka0wrbf01y.png)
Where h represents her height (in feet) after t seconds.
Part 1)
Joyce is on the diving board right before she jumps. Therefore, to find the height of the diving board, we can let t = 0, since this is before she had jumped. Hence:
![h(0)=-(0)^2+10(0)+19=19\text{ feet}](https://img.qammunity.org/2022/formulas/mathematics/high-school/admmu997g2hhog83x70n0cc61diwsid74w.png)
The height of the diving board is 19 feet.
Part 2)
Since this is a quadratic, the maximum height will occur at its vertex point.
So, we need to find the vertex. We can use the following formulas:
![\displaystyle \text{Vertex}=\left(-(b)/(2a), f\left(-(b)/(2a)\right)\right)](https://img.qammunity.org/2022/formulas/mathematics/high-school/xfs7vywqhpoam9vahqm9vo8egbwv9ur0sg.png)
In this case, a = -1, b = 10, and c = 19.
So, the t-coordinate of the vertex is:
![\displaystyle t=-((10))/(2(-1))=5\text{ seconds}](https://img.qammunity.org/2022/formulas/mathematics/high-school/eilfrl8jf1r0ehzvyvsjxw006kb88lnd1j.png)
Joyce will reach her maximum height after five seconds.
Part 3)
To find the maximum height, simply substitute this value back into the equation. Hence:
![h(5)=-(5)^2+10(5)+19=44\text{ feet}](https://img.qammunity.org/2022/formulas/mathematics/high-school/o08p9lpvp27uygtffvxpzo7dmhgexovo4k.png)
So, her maximum height is 44 feet in the air.