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The perimeter of the rectangle below is 130 units. Find the value of z

The perimeter of the rectangle below is 130 units. Find the value of z-example-1

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Answer:

9 =z

Explanation:

The perimeter of a rectangle is

P = 2(l+w) where l is the length and w is the width

P = 2(3z+2+ 4z)

Combine like terms

P = 2(7z+2)

Substitute in the perimeter

130 = 2( 7z+2)

Divide each side by 2

130/2 = 2/2 ( 7z+2)

65 = 7z+2

Subtract 2 from each side

65-2 = 7z+2-2

63 = 7z

Divide by 7

63/7 = 7z/7

9 =z

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