Explanation:
We know that the parabola will be able to be factored into y=a(x+2)(x−3)y=a(x+2)(x−3), where aa will be some scaling factor that restricts the parabola to run through the point (5,10)(5,10). To find aa, just substitute values for xx and y,y,
y=a(x+2)(x−3)∣∣∣(5,10)⟹10=a(5+2)(5−3)y=a(x+2)(x−3)|(5,10)⟹10=a(5+2)(5−3)
We can then conclude that a=57a=57. Thus, our parabola is
f(x)=57x2−57x−307f(x)=57x2−57x−307
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Hunter Zeigler
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A. Skodras
, MSc Mathematics & Applied Mathematics
Answered 2 years ago · Author has 697 answers and 1.6M answer views