What volume of the solution contains 0.25 mol of MgCl2, with 0.995 M MgCl2?

asked Jan 17, 2022 228k views

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2 votes

Answer:

0.251 L

Step-by-step explanation:

c (concentration) = n(moles)/v(volume in litres)

0.995 M = 0.25 mol / v

v = 0.25 mol / 0.995 M

v = 0.251 L

Neongrau answered Jan 21, 2022

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