Question

Please help me! I am stuck please please! :(

Answer 1

side AC =
`10√(3)` , angle A=30 degree , angle B=60 degree

Explanation:

using pythagors theorem

a^2 + b^2 =c^2

here a and b are the legs of the triangle whereas c is hypotenuse so,

10^2 + AC^2 = 20^2

100 + AC^2 = 400

AC^2 =400-100

AC^2 =300

AC=
`√(300)`

AC=
`10√(3)`

For angle A

take angle A as reference angle

using sin rule

sin A =opposite/hypotenuse

sin A=
`(10)/(20)`

sin A=
`(1)/(2)`

A=
`sin^(-1) ((1)/(2) )`

A=30 degree

For angle B

angle A + angle B + angle C =180 degree (sum of interior angles of a triangle)

30 + angle B + 90=180

120 + angle B =180

angle B =180-120

angle B =60 degree