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G(x)=x²+5
.
Find g(a+1)-g(a-1)​

1 Answer

3 votes

Answer:

g(a + 1) - g(a - 1) = 4a

Explanation:

g(x) = x^2 + 5,

when x = a+1, g(a+1) = (a+1)^2 + 5.

when x = a-1, g(a-1) = (a-1)^2 +5.

g(a+1)-g(a-1) = (a+1)^2 + 5 - [(a-1)^2 + 5]

= a^2 + 2a + 1 + 5 - [a^2 - 2a + 1 + 5]

= 4a

User Drew Angell
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