Question

Factor by Grouping:

15xy + 35x – 12y – 28
O (3y - 7)(5x + 4)
O (3xy + 7)(5x + 4)
O (3xy - 7)(5x - 4)
O (5x - 4)(3y + 7)

Answer 1

`\longrightarrow{\green{d.\:(5x - 4)(3y + 7)}}`

`\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}`

`15xy + 35x - 12y - 28`

Taking "
`5x`" as common from first two terms and "
`4`" from last two terms, we have

`= 5x(3y + 7) - 4(3y + 7)`

Taking the factor
`(3y+7)` as common,

`= (5x - 4)(3y + 7)`

`\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}`

Answer 2

`(5x - 4)(3y + 7)`

Explanation:

`15xy+35x−12y−28`

`(15xy+35x)−12y−28`

`5x(3y+7)−4(3y+7)`

`(5x - 4)(3y + 7)`

Hope it is helpful...