Answer:
3x^2+14x+8=0
(3x^2+12x) (2x+8)=0
3x(X+4) 2(X+4)=0
so, (3x+2) (X+4)=0
either 3x+2=0
X= -2/3
or X+4=0
X= -4
now sum of solutions so
-2/3+-4
(-2+-12)/3
-14/3
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