1 Answer

Yurko · Answer 1 · 2022-12-07T16:59:21+0000

Answer:

$s(v) \ge 4$

Explanation:

Given

$s(v) = \sqrt[3]{v}$

v = 64 ---- minimum

Required

The range of s

s represents the side length of the cube.

So, first we solve for s in
$s(v) = \sqrt[3]{v}$

Substitute
v = 64

$s = \sqrt[3]{64}$

s = 4

This means that
s = 4 when
v = 64

In other words, the minimum value of s is 4

Hence, the range is:

$s(v) \ge 4$

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