109k views
4 votes
The functions s(V)=3v describes the side lengths, in units, of a cube with the volume of V cubic units

User Alana
by
5.4k points

1 Answer

5 votes

Answer:


s(v) \ge 4

Explanation:

Given


s(v) = \sqrt[3]{v}


v = 64 ---- minimum

Required

The range of s

s represents the side length of the cube.

So, first we solve for s in
s(v) = \sqrt[3]{v}

Substitute
v = 64


s = \sqrt[3]{64}


s = 4

This means that
s = 4 when
v = 64

In other words, the minimum value of s is 4

Hence, the range is:


s(v) \ge 4

User Yurko
by
5.0k points