Answer:
(a)
67.1 s
(b) 2.5 m
(c) 2.5 m
Step-by-step explanation:
initial speed, u = 0 m/s
final speed, v = 70 m/s
acceleration, a = 5 m/s2
distance, s = 1800 m
(a) Use third equation of motion

Let the time is t.
Use first equation of motion
v = u + at
134.2 = 0 + 5 t
t = 67.1 s
(b) Use second equation of motion

(c) Use second equation of motion
