Question

A piece of metal has a weight of 6.5 N when it is in air and 3.0 N when it is submerged into water. What is the buoyant force on the piece of iron?

Answer 1

The buoyant force on the piece of iron is 3.5 newtons.

Step-by-step explanation:

According to the Archimedes' Principle, the piece of metal experiments a buoyant force equal to the weight of the displaced fluid. By Newton's Laws, we have the following formula:

`F_(B) - W_(P)+W_(F) = 0` (1)

Where:

`F_(B)` - Buoyant force on the piece of iron, in newtons.

`W_(P)` - Weight of the piece of metal, in newtons.

`W_(F)` - Weight of the fluid displaced by the piece of metal, in newtons.

`F_(B) = W_(P)-W_(F)`

If we know that
`W_(P) = 6.5\,N` and
`W_(F) = 3\,N`, then the buoyant force on the piece of iron is:

`F_(B) = 6.5\,N - 3\,N`

`F_(B) = 3.5\,N`

The buoyant force on the piece of iron is 3.5 newtons.