Question

Find the equation of a line perpendicular to 2x-y+6=0 through the point (0, -2)

Answer 1

Explanation:

Let's first rearrange so it's easier to look at: y = 2x +6

To find the perpendicular slope you need to find the negative reciprocal of m so flip and change the sign:

m= -1/2

Next plug in the point (0, -2) into the point-slope equation of a line:

`y2 - y1 = ( - 1)/(2) (x2 - x1) \\`

y-(-2) = -1/2 (x-0)

y + 2 = -1/2x

y = -1/2x - 2

Therefore the equation is y = -1/2x - 2