Answer:
16 3/2
Explanation:
So lets go thru each one.
16 3/2 is just 17.5
A square root cancels out a square.
A cubed root cancels out a cube.
So, in the next answer:
16 squared, to the square root is just 16, since the squaring and root cancels out.
64 sqaured to the cube root must be 16. Lets break it all down:
2^6=64. We need to square this, so we can rewrite it as:
64^2 =
![(2^6)^2](https://img.qammunity.org/2022/formulas/mathematics/college/tt1aozy5cqd9ezztlqqpinii499nr2wpul.png)
Normally we add/subtract exponents, but since the 6 exponent is in parethesese, it is multiplied by the 2 exponent. This makes it 2^12. So we can rewrite
as:
![\sqrt[3]{2^1^2}](https://img.qammunity.org/2022/formulas/mathematics/college/tnwzp6xyq9adw7zc6qlnf2q6bgd1d2ngot.png)
Now, when we divide a exponent by a exponent, we subtract.
However, when we root a exponent, it is division.
So it is the 2
![(^1^2)/(^3)](https://img.qammunity.org/2022/formulas/mathematics/college/bn5yzni2wxknuj8pc5z1gbcaszyx2vp43c.png)
=
![2^4](https://img.qammunity.org/2022/formulas/mathematics/college/60jvpw9em0xrmd1p1ne70wyydr0d9zzg7c.png)
Or
16
Finally we have the cubed root of 8^4.
using the same steps as above, 8^4 =
. This equals
![2^1^2](https://img.qammunity.org/2022/formulas/mathematics/college/jsn4bfqdugbqnu0dv36vkbupx1cyvuz1na.png)
Then again, we cube root it.
This is division of the 12 exponent by the 3 root, so we get:
![2^4](https://img.qammunity.org/2022/formulas/mathematics/college/60jvpw9em0xrmd1p1ne70wyydr0d9zzg7c.png)
=
16
So in the end:
A - 17.5
B - 16
C - 16
D - 16
So a is the largest number
Hope this helps!