Question

A 0.5 mol sample of N2 is in a 6L container at 2 atm. what is the temperature of the gas in K

Answer 1

300 K

General Formulas and Concepts:

Atomic Structure

• Diatomic Elements
• Moles

Gas Laws

Ideal Gas Law: PV = nRT

• P is pressure
• V is volume
• n is moles
• R is gas constant
• T is temperature

Step-by-step explanation:

Step 1: Define

Identify variables

[Given] n = 0.5 mol N₂

[Given] V = 6 L

[Given] P = 2 atm

[Given] R = 0.0821 L · atm · mol⁻¹ · K⁻¹

[Solve] T

Step 2: Solve for T

1. Substitute in variables [Ideal Gas Law]: (2 atm)(6 L) = (0.5 mol)(0.0821 L · atm · mol⁻¹ · K⁻¹)T
2. Multiply [Cancel out units]: 12 atm · L = (0.04105 L · atm · K⁻¹)T
3. Isolate T [Cancel out units]: 292.326 K = T
4. Rewrite: T = 292.326 K

Step 3: Check

Follow sig fig rules and round. We are given 1 sig fig as our lowest.

292.326 K ≈ 300 K