Question

Write an equation in the standard form of the line that passes

through (7, -3) and has a y-intercept of 2.

Answer 1

`5x + 7y = 14`

Explanation:

1: Formulate equations/expressions:

`based \: on \: the \: given \: conditions \: formulate \\ b = 2`

2: Write the equations:

`write \: the \: equation \: of \: linear \: function \\ y = mx + b`

3: Substitute:

`y = mx + b \\ b = 2 \: (7 \: - 3) \\ - 3 = m \: . \: 7 + 2`

4: Solve the equation:

`- 3 = m \: . \: 7 + 2 \\ multiply \: the \: monomials \\ - 3 = 7m + 2 \\ rearrange \: unknown \: terms \: to \: the \: left \: of \: the \: equation \\ - 7m = 2 + 3 \\ calculate \: the \: sum \: or \: differences \\ - 7m = 5 \\ divide \: both \: sides \: of \: the \: equations \: by \: the \: coefficient \: variable \\ m = 5 / ( - 7) \\ calculate \\ m = - (5)/(7)`

5: Substitute:

`y = mx + b \\ b = 2 \: m = - (5)/(7) \\ y = - (5)/(7) x + 2`

6: Rewrite the equations:

`y = - (5)/(7) x + 2 \\ standard \: forms \\ find \: the \: required \: form \\ 5x + 7y = 14`

Answer 2

i got 5x+7y=14 from some help