Question

If a truck starts from rest and it has acceleration of 4m/s^2 for 5 seconds and calculate it's final velocity . What will be the distance travelled by th truck during the time interval ?

Answer 1

final velocity:

`v = u + at \\ v = 0 + (4 * 5) \\ v = 20 \: m {s}^( - 1)`

distance:

`s = ut + (1)/(2) a {t}^(2) \\ s = (0 * t) + (1)/(2) (4 * {5}^(2) ) \\ s = 50 \: m`