Question

If p and q vary inversely and p is 9 when q is 16, determine q when pis equal to 18.​

Answer 1

`p \: \alpha \: (1)/(q) \\ p = (k)/(q) \\ k \: is \: a \: constant \: of \: proportionality \\ when \: p \: is \: 9.. \: \: q = 16 \\ 9 = (k)/(16) \\ k = 144 \\ when \: p \: is \: 18 : \\ 18 = (144)/(q) \\ q = (144)/(18) \\ q = 8`