Question

A sealed balloon filled with 5.00 liters of gas has a pressure of 1.49 atm. This balloon is taken under water where the pressure of the gas becomes 7.62

atm. What is the new volume of this gas? (Assume the temperature does not change.)
O 56.7L
0 0.978 L
0 1.02 L
O 2.27L

Answer 1

0.978L

Step-by-step explanation:

Using Boyle's law equation as follows;

P1V1 = P2V2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (L)

V2 = final volume (L)

According to the provided information,

P1 = 1.49 atm

V1 = 5.00 liters

P2 = 7.62 atm

V2 = ?

Using P1V1 = P2V2

1.49 × 5 = 7.62 × V2

7.45 = 7.62V2

V2 = 7.45/7.62

V2 = 0.978L