Question

Imagine that you have 0.75L of a 0.10M HCl solution. If you add 0.35L of water, what is the new concentration of the solution?

Answer 1

`1 \: litre \: contain \: 0.10 \: moles \: of \: hydrochloric \: acid \\ 0.75 \: litres \: contain \: (0.75 * 0.10) \: moles \\ = 0.075 \: moles \\ total \: volume = 0.75 + 0.35 \\ = 1.1 \: litres \\ 1.1 \: litres \: contain \: 0.075 \: moles \\ 1 \: litres \: will \: contain \: ( (1 * 0.075)/(1.1) ) \\ = 0.068 \: mol \: {l}^( - 1)`