Question

A sand deposit contains three distinct horizontal layers of equal thickness. The hydraulic conductivity of the upper and lower layers is 10-3 cm/sec and that of the middle is 10-2 cm/sec. What are the equivalent values of the horizontal and vertical hydraulic conductivities of the three layers, and What is their ratio?

Answer 1

Kh/Kv = 2.8

Step-by-step explanation:

The horizontal conductivity = K1H1+K2H2+K3H3/(H1+H2+H3)

= K1H+K2H+K3H/3H

= K1+K2+K3/3

= 10-3 cm/sec + 10-3 cm/sec + 10-2 cm/sec/3

= 4 * 10^-3 cm/s

Vertical conductivity

= H+H+H/(H/K1 +H/K2+H/K3)

= 3/(1/K1+1/K2+1/K3)

= 1/700 cm/s

Kh/Kv = 4 * 10^-3 cm/s/ 1/700 cm/s

Kh/Kv = 2.8