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What number must you add to complete the square? x^2+28x=11

User KodeTitan
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2 Answers

3 votes
  • x²+28x+11

To complete 2ab of (a+b)²

  • 2ab=28x
  • 2x(b)=28x
  • b=28x/2x
  • b=14
  • b²=196

196 must be added on both sides to get complete square as (x+14)²

User Palden
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4.6k points
0 votes

Answer:

196

Explanation:

Given equation:


x^2+28x=11

Step 1

When completing the square for an equation in the form ax²+bx+c=0, the first step is to move the constant to the right side of the equation.

This has already been done in the given equation:


x^2+28x=11

Step 2

Add the square of half the coefficient of x to both sides.

This forms a perfect square trinomial on the left side:


\implies x^2+28x+\left((28)/(2)\right)^2=11+\left((28)/(2)\right)^2

Simplify:


\implies x^2+28x+14^2=11+14^2


\implies x^2+28x+196=11+196


\implies x^2+28x+196=207

Step 3

Factor the perfect square trinomial on the left side:


\implies (x+14)^2=207

We have now completed the square and can go onto solving the equation.

Therefore, 196 must be added to both sides of the equation to complete the square.

User Ibrahim Chawa
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3.9k points