Final answer:
The correct mathematical constraint that ensures selecting either or both of Project 1 or Project 2 requires selecting either or both of Project 3 or Project 4 is 'b. X1 + X2 ≤ X3 + X4'.
Step-by-step explanation:
The condition mentioned requires that if either Project 1 or Project 2 (or both) are selected, then it is a requirement to also select either Project 3 or Project 4 (or both). To represent this situation in a mathematical constraint, let's denote X1, X2, X3, and X4 as binary variables where 1 represents selecting the project and 0 represents not selecting it. The appropriate constraint from the ones listed that enforces this condition is:
b. X1 + X2 ≤ X3 + X4
This constraint states that the sum of projects 1 and 2 must be less than or equal to the sum of projects 3 and 4. It makes sure that if one or both of the first two projects are selected, then at least one of the last two projects is also selected. If neither project 1 nor project 2 is selected (both X1 and X2 are 0), this constraint will still hold true as it does not necessitate the selection of projects 3 or 4 in that case.