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Given cosθ = -(√24/5) and angle θ is in Quadrant III, what is the exact value of sinθ in simplest form? Simplify all radicals if needed.

User Surui
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1 Answer

1 vote

Answer:


sin \theta = - (1)/(5)

Explanation:

We Know


sin ^2 \theta + cos^2 \theta = 1\\


sin^2 \theta = 1 - cos^2 \theta


= 1 - (-(√(24) )/(5))^2
[\ given : cos \theta = -(√(24) )/(5) \ ]


= 1 - (24)/(25)\\\\= (25 - 24)/(25)\\\\=(1)/(25)


sin ^2 \theta = (1)/(25)\\\\sin \theta = \sqrt {(1)/(25)}\\\\sin \theta = \pm (1)/(5)\\\\Since \ \theta \ is \ in \ III \ Quadrant \ sin \theta = -(1)/(5)

User Raevik
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