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Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.)f(x)=36x−2x^2

User Ivodvb
by
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1 Answer

1 vote

Answer:


x =9 --- the critical point

Explanation:

Given


f(x) =36x -2x^2

Required

Determine the critical numbers

First, we differentiate f(x)


f'(x) = 36 - 4x

Set to 0 and solve for x


36 -4x = 0

Make 4x the subject


4x = 36

Solve for x


x =36/4


x =9

User Zqudlyba
by
8.5k points

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