Answer:
(2x-3)(2x+1)
Explanation:
4x^2 - 4x - 3
we need two numbers that give 12 when multiplied and 4 when subtracted
the numbers are 6 and 2 because 6*2=12 and 6-4=4.
4x^2 - (6-2)x -3
4x^2 -6x +2x -3
take common
2x(2x -3)+1(2x-3)
take (2x-3) as common
(2x-3)(2x*1 + 1*1)
(2x-3)(2x+1)