Question

Loud speaker A vibrates 200 times each second. Loud speaker B vibrates 400 times each second.a)What is the frequency of the sound produced by Loud speaker A ? Give the value and unit.

b)Which loudspeaker produces higher frequency of vibrations?
(Show calculations)

Answer 1

For a: The frequency produced by loudspeaker A is 200 Hz

For b: Loudspeaker B produces a higher frequency of vibrations.

Step-by-step explanation:

To calculate the frequency of a loudspeaker, we use the formula:

`\\u=\frac{\text{Number of vibrations}}{\text{Time period}}` ......(1)

where,

`\\u` = frequency

• For loudspeaker A:

Number of vibrations = 200

Time period = 1 second

Putting values in equation 1:

`\\u_A=(200)/(1s)=200Hz`

• For loudspeaker B:

Number of vibrations = 400

Time period = 1 second

Putting values in equation 1:

`\\u_B=(400)/(1s)=400Hz`

Hence, the frequency produced by loudspeaker A is 200 Hz and loudspeaker B produces a higher frequency of vibrations.