Question

How much energy is released when 2.25kg of water cools from 99.5°C to 4.2°C? 1000g=1kg; 1000J=1kJ; specific heat of water 4.184J/g°C. q=mc∆T

Answer 1

897154.2 J

Step-by-step explanation:

Applying,

q = mcΔT.............. Equation 1

Where q = amount of energy released, m = mass of water, c = specific heat capacity of water, ΔT = Change in temperature

From the question,

Given: m = 2.25 kg = 2250 g, c = 4.184 J/g°C, ΔT = (4.2-99.5) = -95.3°C

Substitute these values into equation 1

q = 2250(4.184)(-95.3)

q = -897154.2 J

q =

Hence the amount of heat released is 897154.2 J