Question

HELP ASAP PLEASE I NEED ANS N SOLUTION

A bowl contains 25 chips numbered 1 to 25. If a chip is drawn randomly from the bowl, what is the probability that it is
a. 9 or 10?
b. even or divisible by 3?
c. divisible by 5 and divisible by 10?

Answer 1

Given:

A bowl contains 25 chips numbered 1 to 25.

A chip is drawn randomly from the bowl.

To find:

The probability that it is

a. 9 or 10?

b. even or divisible by 3?

c. divisible by 5 and divisible by 10?

Solution:

a. We have,

Number of total chips = 25

Favorable out comes are either 9 or 10. So,

Number of favorable outcomes = 2

The probability that the selected chip is either 9 or 10 is:

`\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Number of total outcomes}}`

`\text{Probability}=(2)/(25)`

Therefore, the probability that the selected chip is either 9 or 10 is
`(2)/(25)`.

b. The numbers that are even from 1 to 25 are 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24.

The numbers from 1 to 25 that are divisible by 3 are 3, 6, 9, 12, 15, 18, 21, 24.

The numbers that are either even or divisible by 3 are 2, 3, 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24.

Number of favorable outcomes = 16

The probability that the selected chip is either even or divisible by 3 is:

`\text{Probability}=(16)/(25)`

Therefore, the probability that the selected chip is either even or divisible by 3 is
`(16)/(25)`.

c. The numbers from 1 to 25 that are divisible by 5 are 5, 10, 15, 20, 25.

The numbers from 1 to 25 that are divisible by 10 are 10, 20.

The numbers that are divisible by both 5 and 10 are 10 and 20.

Number of favorable outcomes = 2

The probability that the selected chip is divisible by 5 and divisible by 10 is:

`\text{Probability}=(2)/(25)`

Therefore, the probability that the selected chip is divisible by 5 and divisible by 10 is
`(2)/(25)`.