Question

Can someone help me with this please I have to have it done ??

Answer 1

Given:

The scale factor of the actual sports utility vehicle to the toy model is 50:1.

Actual length = 7 feet

Actual width = 5 feet

To find:

The length and width of the toy model.

Solution:

a. Let l be the length of the toy model, then

`\frac{\text{Actual length}}{\text{Length of the toy model}}=(50)/(1)`

`(7)/(l)=(50)/(1)`

`7=50l`

`(7)/(50)=l`

`0.14=l`

Therefore, the length of the toy model is 0.14 feet.

b. Let w be the width of the toy model, then

`\frac{\text{Actual width}}{\text{Width of the toy model}}=(50)/(1)`

`(5)/(w)=(50)/(1)`

`5=50w`

`(5)/(50)=w`

`0.10=w`

Therefore, the width of the toy model is 0.10 feet.