Question

What are the roots of the quadratic equation below? 3x^2+15x-5=0

Answer 1

X1 =
`(=15+√(285) )/(6)` and X2 =
`(-15-√(285) )/(6)`

Explanation:

To find the roots of a quadratic equation, you need to solve the quadratic equation by using the quadratic formula.

OR

You can use the (Equation/Function) mode on the calculator.

`\frac{-b+-\sqrt{b^(2) -4ac } }{2a} x \\eq 0`

For this equation,

a = 3

b = 15

c = -5

X1 =
`\frac{-15+\sqrt{15^(2) -4(3)(-5) } }{2(3)} x \\eq 0`

X2 =
`\frac{-15-\sqrt{15^(2) -4(3)(-5) } }{2(3)} x \\eq 0`

Solving this on the calculator and you should get

X1 =
`(=15+√(285) )/(6)` X2 =
`(=15-√(285) )/(6)`

a, b, c = constants, where a ≠ 0

x = the unknown