Question

A 8.6*10^ -6 C charge is places 1.00 m away from a 2.3 * 10 ^ - 4 * C charge. How large is the force of repulsion between the two charges?

Answer 1

The force of repulsion is 17.802 N

Step-by-step explanation:

Given;

magnitude of the first charge, q₁ = 8.6 x 10⁻⁶ C

magnitude of the second charge, q₂ = 2.3 x 10⁻⁴ C

distance between the two charges, r = 1 m

The force of repulsion is calculated using Coulomb's law;

`F = (Kq_1q_2)/(r^2) \\\\F = (9* 10^9 * 8.6* 10^(-6) * 2.3* 10^(-4))/(1^2) \\\\F = 17.802 \ N`

Therefore, the force of repulsion is 17.802 N