Find the value of c that makes x^2–6x + c a perfect square trinomial and write as a binomial squared.

Question

asked Oct 9, 2022 230k views

1 Answer

Fabio Cortez · Answer 1 · 2022-10-13T10:44:27+0000

Answer: 9

Explanation:

Given

The function is
x^2-6x+c

To make it a perfect square, compare it with
(a-b)^2=a^2+b^2-2ab

Here,

$x=a,\\-6x=-2ab\\\\\therefore b=3$

So, c must be square of b i.e. 9

$x^2-6x+c\Rightarrow x^2-6x+9\\\Rightarrow (x-3)^2$

Therefore, value of c is 9.