Question

What is the heat of a reaction, in joules, with a total reaction mixture volume of 61.2 mL if the reaction causes a temperature change of 4.6 oC in a calorimeter

Answer 1

1178J is the heat of the reaction

Step-by-step explanation:

Assume that the reaction mixture has a density of 1.00 g/mL and a specific heat of 4.184 J/g-oC. The calorimeter has a heat capacity of 10.0 J/oC

The heat of a reaction follows the equation:

Q = m*S*ΔT

Where Q is the heat of the reaction,

m is the mass:

61.2mL * (1.00g/mL) = 61.2g

S is specific heat = 4.184J/g°C

ΔT = 4.6°C

Replacing:

Q = 61.2g*4.184J/g°C*4.6°C

Q = 1178J is the heat of the reaction