110k views
4 votes
Two point charges exert a 6.10 N force on each other. What will the force become if the distance between them is increased by a factor of 8

User Yuri G
by
4.4k points

1 Answer

3 votes

Answer:

0.0953125 N

Step-by-step explanation:

Applying,

F = kq'q/r²................. Equation 1

Where F = electrostatic force, k = coulomb's constant, q' and q = first and second charge respectively, r = distance between the charge.

From the equation,

If both charges remain constant,

Therefore,

F = C/r²

C = Constant = product of the two charge(q' and q) and k

Fr² = F'r'²................ Equation 2

From the question,

Given: F = 6.10 N

Assume: r = x m, r' = 8x

Substitute these value into equation 2

6.1(x²) = F'(8x)²

F' = 6.1/64

F' = 0.0953125 N

Hence the new force will become 0.0953125 N

User Mark Kasson
by
4.0k points