Question

How many grams of Al2O3 is extracted from 250. g of FeO?

Answer 1

`m_(Al_2O_3)=118.27gAl_2O_3`

Step-by-step explanation:

Hello there!

In this case, if we consider the following chemical reaction, whereby Al2O3 is produced from Al and FeO:

`3FeO+2Al\rightarrow 3Fe+Al_2O_3`

Thus, since there is 3:1 mole ratio of FeO to Al2O3, it turns out feasible for us to use their molar masses, 71.844 g/mol and 101.96 g/mol respectively, to obtain the grams of the latter as follows:

`m_(Al_2O_3)=250.gFeO*(1molFeO)/(71.844gFeO)*(1molAl_2O_3)/(3molFeO) *(101.96gAl_2O_3)/(1molAl_2O_3)\\\\m_(Al_2O_3)=118.27gAl_2O_3`

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