108k views
0 votes
If r=BT^2 I + ct^3 j, where b and c are positive constants. When does the position vector make an angle 45 with x and y axes

1 Answer

3 votes

Answer:
t=(b)/(c)

Step-by-step explanation:

Given

The position vector is
\vec{r}=bt^2\hat{i}+ct^3\hat{j}\\

So, the angle made by position vector is
45^(\circ) at


\Rightarrow \tan 45^(\circ)=(r_y)/(r_x)\\\\\Rightarrow \tan 45^(\circ)=(ct^3)/(bt^2)\\\\\Rightarrow bt^2=ct^3\\\\\Rightarrow t=(b)/(c)

At
t=(b)/(c), position vector makes
45^(\circ) with x and y axes

User CAD
by
7.6k points