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55. REASONING How many solutions does the equation ax2 + bx + c = 0 have when a and c have different signs? Explain your reasoning.

55. REASONING How many solutions does the equation ax2 + bx + c = 0 have when a and c have different signs? Explain your reasoning.
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4 votes
55. REASONING How many solutions does the equation

ax2 + bx + c = 0 have when a and c have different
signs? Explain your reasoning.

User Ptrn
by
8.2k points

1 Answer

2 votes
it will have 2 solutions! this is because a negative and a negative cancel each other out and will make a positive under the radical.
User Stijn Hoste
by
7.9k points
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