On a Space shuttle, LiOH Is used to absorb CO2 to produce LiHCO3
LiOH + CO2 === LiHCO3
Now
58g of CO2 produces 79.3g of LiHCO3
This is the Actual Yield.
Recall
% Yield = Actual yield/Theoretical yield x100
NOW
We have to find the theoretical yield
From the equation of reaction
Now 58g of CO2 reacted
Converting to Moles
mole = Mass/Molar Mass
Molar mass of CO2=44g/mol
Mole = 58/44
=1.318moles of CO2
From the equation Of Reaction.
1 mole of CO2 reacts and Produces 1 mole of LiHCO3
Since their Mole ratio is 1:1
An Equal amount of LiHCO3 will be produced.
So 1.318moles of LiHCO3 will be produced.
Convert this mole to Mass
Mole =Mass/Molar Mass
Mass = Mole x Molar Mas
Molar Mass of LiHCO3 =68g/mol
Mass = 1.318 x 68
Mass = 89.62g.
This is the theoretical Yield.
% yield = 79.3/89.62 x 100
= 88.48%.