Question

A 575.4575.4 mL sample of carbon dioxide was heated to 377377 K. If the volume of the carbon dioxide sample at 377377 K is 824.7824.7 mL, what was its temperature at 575.4575.4 mL

Answer 1

263 K

Step-by-step explanation:

Assuming ideal behaviour and constant pressure, we can solve this problem by using Charles' law, which states that at constant pressure:

• T₁V₂=T₂V₁

In this case:

• T₁ = ?

• V₂ = 824.7 mL

• T₂ = 377 K

• V₁ = 575.45 mL

We input the data:

• T₁ * 824.7 mL = 377 K * 575.45 mL

And solve for T₁:

• T₁ = 263 K