Question

Please help ASAP I need to pass this

Answer 1

Explanation:

`\left\{\begin{array}{ccc}y=(3)/(4)x&(1)\\(5)/(2)x+2y=5&(2)\end{array}\right\\\\\text{substitute (1) to (2)}\\\\(5)/(2)x+2\left(\boxed{(3)/(4)x}\right)=5\\\\(5)/(2)x+(6:2)/(4:2)x=5\\\\(5)/(2)x+\boxed{(3)/(2)x}=5\qquad|\text{combine like terms}\\\\(5+3)/(2)x=5\\\\(8)/(2)x=5\\\\\boxed{4x=5}\qquad|\text{divide both sides by 4}\\\\(4x)/(4)=(5)/(4)\\\\\boxed{x=(5)/(4)}`

`\text{Put it to (1):}\\\\y=(3)/(4)\left(\boxed{(5)/(4)}\right)\\\\y=(3\cdot5)/(4\cdot4)\\\\y=\boxed{(15)/(16)}`