Question

What is the perimeter in terms of x, of the rectangle shown here (x^2+7x-9) (3x^2-2x)

Answer 1

Given:

Consider the dimensions of the rectangle are
`(x^2+7x-9)` and
`(3x^2-2x)`.

To find:

The perimeter in terms of x, of the rectangle.

Solution:

Let the length of the rectangle be
`(x^2+7x-9)` and the width of the rectangle is
`(3x^2-2x)` units.

The perimeter of a rectangle is:

`P=2(l+w)`

Where, l is the length and w is the width of the rectangle.

Substituting
`l=(x^2+7x-9)` and
`w=(3x^2-2x)` in the above formula, we get

`P=2((x^2+7x-9)+(3x^2-2x))`

`P=2(4x^2+5x-9)`

`P=2(4x^2)+2(5x)+2(-9)`

`P=8x^2+10x-18`

Therefore, the perimeter of the rectangle is
`8x^2+10x-18` units.