148k views
1 vote
What is the perimeter in terms of x, of the rectangle shown here (x^2+7x-9) (3x^2-2x)

1 Answer

2 votes

Given:

Consider the dimensions of the rectangle are
(x^2+7x-9) and
(3x^2-2x).

To find:

The perimeter in terms of x, of the rectangle.

Solution:

Let the length of the rectangle be
(x^2+7x-9) and the width of the rectangle is
(3x^2-2x) units.

The perimeter of a rectangle is:


P=2(l+w)

Where, l is the length and w is the width of the rectangle.

Substituting
l=(x^2+7x-9) and
w=(3x^2-2x) in the above formula, we get


P=2((x^2+7x-9)+(3x^2-2x))


P=2(4x^2+5x-9)


P=2(4x^2)+2(5x)+2(-9)


P=8x^2+10x-18

Therefore, the perimeter of the rectangle is
8x^2+10x-18 units.

User Skylar Anderson
by
6.4k points