Question

Consider an urn with 7 black balls, 3 yellow balls, and 4 orange balls. If 3 balls are chosen randomly with replacement, what is the probability that the first is yellow, the second is orange, and the third is orange

Answer 1

1.79% chance or
`(6)/(343)`

Explanation:

7+3+4=14

chance of yellow
`(3)/(14)`

chance of orange
`(4)/(14)`

`(3)/(14) * (4)/(14) *(4)/(14) = (6)/(343)`