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An empty 12,954 kg railroad car, traveling at a speed of 28 m/s strikes a partially filled 17,616 kg railroad car moving in the same direction at a speed of 5 m/s. What is the total momentum of the two
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An empty 12,954 kg railroad car, traveling at a speed of 28 m/s strikes a partially filled 17,616 kg railroad car moving in the same direction at a speed of 5 m/s. What is the total momentum of the two railroad cars AFTER the collision?

User Trank
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5.1k points

1 Answer

7 votes

Answer:

450792 kgm/s

Step-by-step explanation:

by conservation of momentum,

total momentum AFTER collision = total momentum BEFORE collision

=mv+m'v'

=12954×28+17616×5

=450792 kgm/s

User Sagar Jogadia
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4.6k points
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