84.3k views
1 vote
A 17 kg box experiences an applied force of +175 N and a force of friction of -125 N. While experiencing these unbalanced forces, the box travels a total of 15.0 meters in 5.25 seconds.

Calculate the power developed by the unbalanced forces to move the box.



A
44.1 watts
B
143 watts
C
263 watts
D
750 watts

1 Answer

3 votes

Answer: (b)

Step-by-step explanation:

Given

Mass of box
m=17\ kg

Applied force
F=175\ N

Friction force
f=-125\ N

Box travels a distance of
s=15\ m

time taken
t=5.25\ s

Net unbalanced force
F_(net)=175-125=50\ N

Work done by the unbalanced force


\Rightarrow W=F_(un)\cdot s\\\Rightarrow W=50* 15\\\Rightarrow W=750\ N

Power developed by unbalanced force


\Rightarrow P=(W)/(t)\\\\\Rightarrow P=(750)/(5.25)\\\\\Rightarrow P=142.85\approx 1423\ W

Thus, option (b) is correct.

User Asok Buzz
by
7.3k points