Question

Two buildings on opposite sides of a street are 40 meters apart. From the top of the shorter building, which is 176 meters high, the angle of elevation to the top of the taller building is 13 degrees. Find the height of the taller building to the nearest meter. *

Answer 1

185 m

Explanation:

From the solution diagram shown :

The height of the taller building is :

(Height of shorter building + h)

Height of shorter building is given as 176 m

The height, h can be obtained using Pythagoras :

Tan θ = opposite / Adjacent

Tan 13 = h / 40

h = tan 13 * 40

h = 9.235 m

Hence, height of taller building :

176 m + 9.235 m

= 185.235 m

= 185 m