Question

What is the resistance of a 3.5 m copper wire (Rho= 1.7x10-8 Ohm·m) that 1 point

has a cross-sectional area of 5.26x10-6 m2? Use the equation below. *
R=
pl
А
4.1 x 10-3 ohms
1.1 x 10 3 ohms
9.2 x 10-4 ohms
1.1x 10-2 ohms

Answer 1

(D)

Step-by-step explanation:

Given :

l=3.5 m

`A=5.26*10^(-6)`
`m^(2)`

`p=1.7*10^(-8) ohm.m`

Resistance can be calculated as :

`R=p(l)/(A) \\R=1.7*10^(-8) (3.5)/(5.26*10^(-6) )`

`R=(5.95*10^(-2) )/(5.26) \\R=1.13*10^(-2)`

Resistance of the wire will be 1.1×
`10^(-2)` ohms

Option D is correct